64=3x^2+5x^2

Solution for 64=3x^2+5x^2 equation:

64=3x^2+5x^2

We move all terms to the left:

64-(3x^2+5x^2)=0

We get rid of parentheses

-3x^2-5x^2+64=0

We add all the numbers together, and all the variables

-8x^2+64=0

a = -8; b = 0; c = +64;
Δ = b2-4ac
Δ = 02-4·(-8)·64
Δ = 2048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2048}=\sqrt{1024*2}=\sqrt{1024}*\sqrt{2}=32\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{2}}{2*-8}=\frac{0-32\sqrt{2}}{-16}
=-\frac{32\sqrt{2}}{-16}
=-\frac{2\sqrt{2}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{2}}{2*-8}=\frac{0+32\sqrt{2}}{-16}
=\frac{32\sqrt{2}}{-16}
=\frac{2\sqrt{2}}{-1}
$